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In many cases, it is useful to have a constructor or factory method that validates arguments before instantiating an object, returning a new object if the arguments are valid and null otherwise.

But in traditional javascript constructors, you're limited in what you can return. In particular, you cannot return null.

Is there a preferred programming pattern that accomplishes this, ideally honoring inheritance? Conceptually, I'm looking for something like this (I know this code cannot work):

// This RootClass code can't possibly work -- it's for illustration only
function RootClass() {};
RootClass.prototype.constructor = RootClass;
RootClass.createValidated(arg) {
  return isArgValid(arg) ? originalConstructor(arg) : null;
}

// example subclass
function OddsOnly(arg) { this._arg = arg; }
OddsOnly.prototype = Object.create(RootClass.prototype);
OddsOnly.prototype.constructor = OddsOnly;
OddsOnly.prototype.isArgValid = function(x) { return x & 1; };

// example calls
var a = OddsOnly.createValidated(3); // => OddsOnly { _arg: 3 }
var b = OddsOnly.createValidated(2); // => null

(Extra credit: is there a way to hide or obfuscate the new method so you must use the createValidated() method?)

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  • Have you considered throwing an error on an invalid action as an alternative, effectively terminating the application if a try/catch block is not used and the error properly handled? Although JS is prototype based, throwing constructors are very common among OO languages and I am pretty sure the pattern may be applied to JS too (even more so with ES6, which even supports the class keyword by default).
    – Andy
    Jun 12, 2016 at 11:16
  • @DavidPacker: thank you. Yes, I've considered the throw/catch approach to argument checking. Even though it feels heavy handed, it may be the simplest and ultimately cleanest solution. Jun 12, 2016 at 14:22

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