1

In Scheme, the general form of a procedure definition is:

(define (<name> <parameters>) <body>)

where <body> accepts a sequence of expressions, allowing this kind of procedure definitions:

> (define (f) 1 2 3)
> (f)
3

Likewise, the general form of a conditional expression is:

(cond (<predicate> <consequent>) (<predicate> <consequent>) … (<predicate> <consequent>))

where <consequent> in each clause accepts a sequence of expressions, allowing this kind of conditional expressions:

> (cond (#t 1 2 3))
3

But why can’t I use define in a clause’s consequent of a conditional expression like in the body of a procedure definition?

Compare:

> (define (f) (define x 1) (define y 1) (define z 1) (+ x y z))
> (f)
3

with:

> (cond (#t (define x 1) (define y 1) (define z 1) (+ x y z)))
ERROR on line 1: unexpected define: (define x 1)

Note. — I am using the Chibi-Scheme 0.8.0 implementation on MacOS 10.15.2.

1 Answer 1

2

define can only be used at either the top-level, or at the beginning of a body. It cannot be used in other places where expressions can be used. Here is the relevant quote from R5RS:

Definitions are valid in some, but not all, contexts where expressions are allowed. They are valid only at the top level of a <program> and at the beginning of a <body>.

The cases of a cond are not bodys, and so you cannot put a define there.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.