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Jul 21, 2011 at 17:58 comment added configurator @Sjoerd: But you need a base class with the shared implementation; that can't be an interface.
Jul 21, 2011 at 17:22 comment added Sjoerd An interface can't be instantiated either.
Jul 21, 2011 at 15:47 history answered configurator CC BY-SA 3.0