Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with typescript
Search options not deleted
user 246716
Programming language created by Microsoft. Open source, and compiles to JavaScript.
3
votes
Accepted
Why don't variables in TypeScript implicitly infer literal typing?
From @amon's comment:
this behaviour indicates that the type checker does not inherit this info from the interface, but first type-checks the class (incl. type inference for foo) and then checks w …
- 292
2
votes
2
answers
342
views
Why don't variables in TypeScript implicitly infer literal typing?
Given a literal type, for instance 1 | 2, assigning a value to a variable that correctly corresponds to the literal type will fail.
interface SomeInterface {
foo: (1 | 2);
}
class SomeClass imple …
- 292